Files
tippecanoe/polygon.cpp
T

887 lines
25 KiB
C++

#include <stdio.h>
#include <algorithm>
#include <set>
#include <vector>
#include <cmath>
#include <climits>
#include <limits>
#include "geometry.hpp"
#include "errors.hpp"
struct point {
long long x;
long long y;
point(long long x_, long long y_)
: x(x_), y(y_) {
}
point() {
x = 0;
y = 0;
}
bool operator<(point const &s) const {
if (y < s.y || (y == s.y && x < s.x)) {
return true;
} else {
return false;
}
}
bool operator==(point const &s) const {
return y == s.y && x == s.x;
}
bool operator!=(point const &s) const {
return !(*this == s);
}
};
typedef std::pair<point, point> segment;
bool spindle_visible(segment const &seg, long long extent) {
if (extent == 0) {
// extent of 0 means no spindle revival
return false;
}
long long minx = std::min(seg.first.x, seg.second.x);
long long miny = std::min(seg.first.y, seg.second.y);
long long maxx = std::max(seg.first.x, seg.second.x);
long long maxy = std::max(seg.first.y, seg.second.y);
if (maxx <= 0 || maxy <= 0 || minx >= extent || miny >= extent) {
return false;
} else {
return true;
}
}
bool fix_opposites(std::vector<segment> &segs, long long extent) {
bool changed = false;
std::multimap<segment, size_t> opposites;
segment erased = std::make_pair(point(INT_MAX, INT_MAX), point(INT_MAX, INT_MAX));
for (size_t i = 0; i < segs.size(); i++) {
segment opposite = std::make_pair(segs[i].second, segs[i].first);
opposites.emplace(opposite, i);
}
for (size_t i = 0; i < segs.size(); i++) {
if (segs[i] == erased) {
continue;
}
auto f = opposites.equal_range(segs[i]);
for (; f.first != f.second; ++f.first) {
if (segs[f.first->second] == erased) {
continue;
}
long long dx = segs[i].second.x - segs[i].first.x;
long long dy = segs[i].second.y - segs[i].first.y;
long long dsq = dx * dx + dy * dy;
if (spindle_visible(segs[i], extent) && dsq >= 5 * 5) {
// alter the segment instead to keep it from collapsing away
double ang = atan2(dy, dx) - M_PI / 2;
long long cx = std::llround((segs[i].second.x + segs[i].first.x) / 2.0 + sqrt(2) / 2.0 * cos(ang));
long long cy = std::llround((segs[i].second.y + segs[i].first.y) / 2.0 + sqrt(2) / 2.0 * sin(ang));
segs.emplace_back(point(cx, cy), segs[i].second);
segs[i] = std::make_pair(segs[i].first, point(cx, cy));
changed = true;
// segs[i] is not erased, so segs[f.first->second]
// will still match against it and will be bowed out
// in the opposite direction.
} else {
segs[i] = erased;
segs[f.first->second] = erased;
}
opposites.erase(f.first);
break;
}
}
size_t out = 0;
for (size_t i = 0; i < segs.size(); i++) {
if (segs[i] != erased) {
segs[out++] = segs[i];
}
}
segs.resize(out);
return changed;
}
const std::pair<double, double> SAME_SLOPE = std::make_pair(-INT_MAX, INT_MAX);
// https://stackoverflow.com/questions/563198/how-do-you-detect-where-two-line-segments-intersect
//
// beware of
// https://stackoverflow.com/questions/9043805/test-if-two-lines-intersect-javascript-function/16725715#16725715
// which does not seem to produce correct results.
std::pair<double, double> get_line_intersection(long long p0_x, long long p0_y, long long p1_x, long long p1_y,
long long p2_x, long long p2_y, long long p3_x, long long p3_y) {
// bounding box reject, x
long long min01x = std::min(p0_x, p1_x);
long long max01x = std::max(p0_x, p1_x);
long long min23x = std::min(p2_x, p3_x);
long long max23x = std::max(p2_x, p3_x);
if (max01x < min23x || max23x < min01x) {
return std::make_pair(-1, -1);
}
// bounding box reject, y
long long min01y = std::min(p0_y, p1_y);
long long max01y = std::max(p0_y, p1_y);
long long min23y = std::min(p2_y, p3_y);
long long max23y = std::max(p2_y, p3_y);
if (max01y < min23y || max23y < min01y) {
return std::make_pair(-1, -1);
}
long long d01_x, d01_y, d23_x, d23_y;
d01_x = p1_x - p0_x;
d01_y = p1_y - p0_y;
d23_x = p3_x - p2_x;
d23_y = p3_y - p2_y;
long long det = (-d23_x * d01_y + d01_x * d23_y);
if (det != 0) {
double t, s;
t = (d23_x * (p0_y - p2_y) - d23_y * (p0_x - p2_x)) / (double) det;
s = (-d01_y * (p0_x - p2_x) + d01_x * (p0_y - p2_y)) / (double) det;
return std::make_pair(t, s);
}
return SAME_SLOPE;
}
bool vertical(std::vector<segment> &segs, size_t s, long long y) {
if ((y > segs[s].first.y && y < segs[s].second.y) ||
(y > segs[s].second.y && y < segs[s].first.y)) {
segs.push_back(std::make_pair(point(segs[s].first.x, y), segs[s].second));
segs[s] = std::make_pair(segs[s].first, point(segs[s].first.x, y));
return true;
}
return false;
}
bool horizontal(std::vector<segment> &segs, size_t s, long long x) {
if ((x > segs[s].first.x && x < segs[s].second.x) ||
(x > segs[s].second.x && x < segs[s].first.x)) {
double slope = (segs[s].second.y - segs[s].first.y) /
(double) (segs[s].second.x - segs[s].first.x);
long long y = std::llround(segs[s].first.y + slope * (x - segs[s].first.x));
segs.push_back(std::make_pair(point(x, y), segs[s].second));
segs[s] = std::make_pair(segs[s].first, point(x, y));
return true;
}
return false;
}
bool intersect_collinear(std::vector<segment> &segs, size_t s1, size_t s2) {
bool changed = false;
if (segs[s1].first.x == segs[s1].second.x) {
// vertical
if (segs[s2].first.x == segs[s2].second.x) {
// in which case the other one should also be vertical
if (segs[s1].first.x == segs[s2].first.x) {
// collinear, not parallel
if (vertical(segs, s1, segs[s2].first.y)) {
changed = true;
}
if (vertical(segs, s1, segs[s2].second.y)) {
changed = true;
}
if (vertical(segs, s2, segs[s1].first.y)) {
changed = true;
}
if (vertical(segs, s2, segs[s1].second.y)) {
changed = true;
}
}
} else {
fprintf(stderr, "One segment is vertical and the other is not %lld,%lld to %lld,%lld; %lld,%lld to %lld,%lld.\n",
segs[s1].first.x, segs[s1].first.y, segs[s1].second.x, segs[s1].second.y,
segs[s2].first.x, segs[s2].first.y, segs[s2].second.x, segs[s2].second.y);
exit(EXIT_IMPOSSIBLE);
}
} else {
// horizontal or diagonal
double slope1 = (segs[s1].second.y - segs[s1].first.y) /
(double) (segs[s1].second.x - segs[s1].first.x);
double slope2 = (segs[s2].second.y - segs[s2].first.y) /
(double) (segs[s2].second.x - segs[s2].first.x);
if (slope1 == slope2) {
// they are parallel. do they have the same y intercept?
long long y1 = std::llround(segs[s1].first.y + slope1 * (0 - segs[s1].first.x));
long long y2 = std::llround(segs[s2].first.y + slope1 * (0 - segs[s2].first.x));
if (y1 == y2) {
// collinear, not parallel
if (horizontal(segs, s1, segs[s2].first.x)) {
changed = true;
}
if (horizontal(segs, s1, segs[s2].second.x)) {
changed = true;
}
if (horizontal(segs, s2, segs[s1].first.x)) {
changed = true;
}
if (horizontal(segs, s2, segs[s1].second.x)) {
changed = true;
}
}
} else {
fprintf(stderr, "One segment has a slope of %f and the other %f: %lld,%lld to %lld,%lld; %lld,%lld to %lld,%lld.\n",
slope1, slope2,
segs[s1].first.x, segs[s1].first.y, segs[s1].second.x, segs[s1].second.y,
segs[s2].first.x, segs[s2].first.y, segs[s2].second.x, segs[s2].second.y);
exit(EXIT_IMPOSSIBLE);
}
}
return changed;
}
bool intersect(std::vector<segment> &segs, size_t s1, size_t s2) {
auto intersections = get_line_intersection(segs[s1].first.x, segs[s1].first.y,
segs[s1].second.x, segs[s1].second.y,
segs[s2].first.x, segs[s2].first.y,
segs[s2].second.x, segs[s2].second.y);
bool changed = false;
if (intersections.first >= 0 && intersections.first <= 1 && intersections.second >= 0 && intersections.second <= 1) {
long long x = std::llround(segs[s1].first.x + intersections.first * (segs[s1].second.x - segs[s1].first.x));
long long y = std::llround(segs[s1].first.y + intersections.first * (segs[s1].second.y - segs[s1].first.y));
if ((x == segs[s1].first.x && y == segs[s1].first.y) ||
(x == segs[s1].second.x && y == segs[s1].second.y)) {
// at an endpoint in s1, so it doesn't need to be changed
} else {
// printf("introduce %f,%f in %f,%f to %f,%f (s1 %zu %zu)\n", x, y, segs[s1].first.x, segs[s1].first.y, segs[s1].second.x, segs[s1].second.y, s1, s2);
segs.push_back(std::make_pair(point(x, y), segs[s1].second));
segs[s1] = std::make_pair(segs[s1].first, point(x, y));
changed = true;
}
if ((x == segs[s2].first.x && y == segs[s2].first.y) ||
(x == segs[s2].second.x && y == segs[s2].second.y)) {
// at an endpoint in s2, so it doesn't need to be changed
} else {
// printf("introduce %f,%f in %f,%f to %f,%f (s2 %zu %zu)\n", x, y, segs[s2].first.x, segs[s2].first.y, segs[s2].second.x, segs[s2].second.y, s1, s2);
// printf("introduce %lld,%lld in %lld,%lld to %lld,%lld (s2)\n", std::llround(x), std::llround(y), std::llround(segs[s2].first.x), std::llround(segs[s2].first.y), std::llround(segs[s2].second.x), std::llround(segs[s2].second.y));
segs.push_back(std::make_pair(point(x, y), segs[s2].second));
segs[s2] = std::make_pair(segs[s2].first, point(x, y));
changed = true;
}
} else if (intersections == SAME_SLOPE) {
if (intersect_collinear(segs, s1, s2)) {
changed = true;
}
} else {
// could intersect, but does not
}
return changed;
}
struct scan_transition {
long long y;
int kind; // -1 == top, 0 == horizontal, +1 == bottom
size_t segment;
scan_transition(long long y_, bool kind_, size_t segment_)
: y(y_), kind(kind_), segment(segment_) {
}
bool operator<(scan_transition const &s) const {
if (y < s.y) {
return true;
} else if (y == s.y) {
if (kind < s.kind) {
return true;
} else if (kind == s.kind) {
if (segment < s.segment) {
return true;
}
}
}
return false;
}
};
double xcoord(std::vector<segment> const &segs, size_t seg, long long y) {
return 0;
}
void snap_round(std::vector<segment> &segs, long long extent) {
bool again = true;
while (again) {
again = false;
// find identical opposite-winding segments and adjust for them
//
// this is in the same loop because we may introduce new self-intersections
// in the course of trying to keep spindles alive, and will then need to
// resolve those.
if (fix_opposites(segs, extent)) {
again = true;
}
// set up for a scanline traversal of the segments
// to find the pairs that intersect
// while not looking at pairs that can't possibly intersect
// index by y coordinates
std::vector<scan_transition> transitions;
for (size_t i = 0; i < segs.size(); i++) {
if (segs[i].first.y < segs[i].second.y) {
transitions.emplace_back(segs[i].first.y, -1, i); // top
transitions.emplace_back(segs[i].second.y, 1, i); // bottom
} else if (segs[i].first.y > segs[i].second.y) {
transitions.emplace_back(segs[i].second.y, -1, i); // top
transitions.emplace_back(segs[i].first.y, 1, i); // bottom
} else {
transitions.emplace_back(segs[i].first.y, 0, i); // horizontal
}
}
std::sort(transitions.begin(), transitions.end());
// do the scan
std::vector<std::pair<double, size_t>> active;
size_t i = 0;
while (i < transitions.size()) {
long long y = transitions[i].y;
// update the active positions to correspond to the new Y coordinate
for (size_t j = 0; j < active.size(); j++) {
long long x = xcoord(segs, active[j].second, y);
// look for anything that might be collinear with this segment
// (has the same x coordinate above; still has the same
// x coordinate here).
for (size_t k = j + 1; k < active.size() && active[k].first == active[j].first; k++) {
long long kx = xcoord(segs, active[k].second, y);
if (kx == x) {
if (intersect(segs, active[j].second, active[k].second)) {
again = true;
}
}
}
active[j].first = x;
}
// are they still in order?
for (size_t j = 0; j < active.size(); j++) {
for (size_t k = j; k + 1 < active.size() && active[k].first > active[k + 1].first; k++) {
// no, they are out of order. bubble them into order,
// and check where the intersection was at each step
std::swap(active[k], active[k + 1]);
if (intersect(segs, active[k].second, active[k + 1].second)) {
again = true;
} else {
fprintf(stderr, "can't happen: they don't actually intersect?\n");
exit(EXIT_IMPOSSIBLE);
}
}
}
// activate any new tops at this y coordinate
for (; i < transitions.size() && transitions[i].kind < 0 && transitions[i].y == y; i++) {
std::pair<double, size_t> top(xcoord(segs, transitions[i].segment, y), transitions[i].segment);
auto where = std::upper_bound(active.begin(), active.end(), top);
active.insert(where, top);
}
// check any horizontals at this y coordinate against the active set
// and check collinear horizontals against each other
for (; i < transitions.size() && transitions[i].kind == 0 && transitions[i].y == y; i++) {
}
// deactivate any bottoms at this y coordinate
for (; i < transitions.size() && transitions[i].kind > 0 && transitions[i].y == y; i++) {
std::pair<double, size_t> bottom(xcoord(segs, transitions[i].segment, y), transitions[i].segment);
auto where = std::lower_bound(active.begin(), active.end(), bottom);
active.erase(where);
}
}
}
}
// https://www.cuemath.com/geometry/area-of-triangle-in-coordinate-geometry/
double triangle_area(drawvec const &geom, size_t base, size_t increment, size_t len) {
double area = ((double) geom[base + (increment + 0) % len].x * (geom[base + (increment + 1) % len].y - geom[base + (increment + 2) % len].y) +
(double) geom[base + (increment + 1) % len].x * (geom[base + (increment + 2) % len].y - geom[base + (increment + 0) % len].y) +
(double) geom[base + (increment + 2) % len].x * (geom[base + (increment + 0) % len].y - geom[base + (increment + 1) % len].y)) /
2;
return area;
}
struct ring_area {
drawvec geom;
double area;
std::vector<size_t> children;
long long ear_x;
long long ear_y;
ring_area(drawvec geom_, double area_) {
geom = geom_;
area = area_;
// search polygon ears to find an interior point
for (size_t i = 0; i + 2 < geom.size(); i++) {
long long x = (geom[i].x + geom[i + 1].x + geom[i + 2].x) / 3;
long long y = (geom[i].y + geom[i + 1].y + geom[i + 2].y) / 3;
if (triangle_area(geom, 0, i, geom.size() - 1) != 0 && pnpoly(geom, 0, geom.size(), x, y)) {
ear_x = x;
ear_y = y;
return;
}
}
fprintf(stderr, "Couldn't find an interior point\n");
exit(EXIT_IMPOSSIBLE);
}
bool operator<(ring_area const &s) const {
// this sorts backwards, so the ring with the largest area comes first
if (std::fabs(area) > std::fabs(s.area)) {
return true;
} else if (std::fabs(area) == std::fabs(s.area)) {
if (geom < s.geom) {
return true;
}
}
return false;
}
};
const int SCALE = 3;
std::vector<ring_area> reassemble(std::vector<segment> const &segs) {
std::multimap<point, segment> connections;
std::vector<ring_area> ret;
for (auto const &seg : segs) {
connections.emplace(seg.first, seg);
}
while (connections.size() > 0) {
// arbitrarily choose a starting point,
// and walk the connections from there until
// we find a point that we have already visited.
// make a copy of the connections so we can remove
// segments from it as we walk, even though some of
// the segments we remove will probably have to go
// back in because they are really part of another ring
std::multimap<point, segment> examining = connections;
std::map<point, segment> examined;
segment here = examining.begin()->second;
examined.emplace(here.first, here);
examining.erase(examining.begin());
// go until the segment that we are looking at
// points to a vertex we have seen before, which
// will be the initial point of the ring
while (examined.find(here.second) == examined.end()) {
auto options = examining.equal_range(here.second);
if (options.first == options.second) {
fprintf(stderr, "can't happen: no connections in ring construction\n");
exit(EXIT_IMPOSSIBLE);
}
// choose the sharpest possible left turn
// (in tile coordinate space, so Y coordinates
// increase toward the bottom) of the available
// connections from this point, which should
// lead around either the largest outer ring or
// the smallest inner ring that includes this point.
auto best = options.first;
double bestang = 500;
for (; options.first != options.second; ++options.first) {
double ang1 = atan2(here.second.y - here.first.y, here.second.x - here.first.x);
double ang2 = atan2(options.first->second.second.y - options.first->second.first.y,
options.first->second.second.x - options.first->second.first.x);
double diff = ang1 - ang2;
// normalize to -180° … 180°
while (diff > M_PI) {
diff -= 2 * M_PI;
}
while (diff < -M_PI) {
diff += 2 * M_PI;
}
// closest to -180 is the best
if (diff < bestang) {
bestang = diff;
best = options.first;
}
}
here = best->second;
examined.emplace(here.first, here);
examining.erase(best);
}
here = examined.find(here.second)->second; // the new initial segment, found above
// now do a second walk, actually removing the connections
// from the original copy, and saving the ring that we make.
examining.clear();
examined.clear();
std::vector<point> ring;
examined.emplace(here.first, here);
ring.push_back(here.first);
// find the initial segment in `connections` so we can remove it
auto initial = connections.equal_range(here.first);
bool found = false;
for (; initial.first != initial.second; ++initial.first) {
if (initial.first->second == here) {
connections.erase(initial.first);
found = true;
break;
}
}
if (!found) {
fprintf(stderr, "can't happen: couldn't find initial point");
exit(EXIT_IMPOSSIBLE);
}
while (here.second != ring[0]) {
auto options = connections.equal_range(here.second);
if (options.first == options.second) {
fprintf(stderr, "can't happen: no connections in ring construction\n");
exit(EXIT_IMPOSSIBLE);
}
// choose the sharpest possible left turn
// (in tile coordinate space, so Y coordinates
// increase toward the bottom) of the available
// connections from this point, which should
// lead around either the largest outer ring or
// the smallest inner ring that includes this point.
auto best = options.first;
double bestang = 500;
for (; options.first != options.second; ++options.first) {
double ang1 = atan2(here.second.y - here.first.y, here.second.x - here.first.x);
double ang2 = atan2(options.first->second.second.y - options.first->second.first.y,
options.first->second.second.x - options.first->second.first.x);
double diff = ang1 - ang2;
// normalize to -180° … 180°
while (diff > M_PI) {
diff -= 2 * M_PI;
}
while (diff < -M_PI) {
diff += 2 * M_PI;
}
// closest to -180 is the best
if (diff < bestang) {
bestang = diff;
best = options.first;
}
}
here = best->second;
examined.emplace(here.first, here);
connections.erase(best);
ring.push_back(here.first);
}
// rotate the ring for idempotence
size_t first = 0;
for (size_t i = 1; i < ring.size(); i++) {
if (ring[i] < ring[first]) {
first = i;
}
}
{
std::vector<point> ring2;
for (size_t i = 0; i < ring.size(); i++) {
ring2.push_back(ring[(i + first) % ring.size()]);
}
ring = std::move(ring2);
}
// these coordinates are scaled, so that `encloses` can always find
// an interior point in each ring
drawvec out;
for (size_t i = 0; i < ring.size(); i++) {
out.emplace_back(i == 0 ? VT_MOVETO : VT_LINETO, ring[i].x * SCALE, ring[i].y * SCALE);
}
out.emplace_back(VT_LINETO, ring[0].x * SCALE, ring[0].y * SCALE);
if (out[0] != out[out.size() - 1]) {
fprintf(stderr, "Ring not closed???\n");
exit(EXIT_IMPOSSIBLE);
}
double area = get_area(out, 0, out.size());
if (area != 0) {
ret.push_back(ring_area(out, area));
} else {
fprintf(stderr, "0-area ring: ");
for (auto const &g : out) {
fprintf(stderr, "%lld,%lld ", (long long) g.x, (long long) g.y);
}
fprintf(stderr, "\n");
}
}
return ret;
}
bool encloses(ring_area const &parent, ring_area const &child) {
if (std::fabs(child.area) > std::fabs(parent.area)) {
fprintf(stderr, "child area %f is greater than parent area %f\n", child.area, parent.area);
exit(EXIT_IMPOSSIBLE);
}
return pnpoly(parent.geom, 0, parent.geom.size(), child.ear_x, child.ear_y);
}
bool same_slope(draw d1, draw d2, draw d3) {
long long dx12 = d2.x - d1.x;
long long dy12 = d2.y - d1.y;
long long dx23 = d3.x - d2.x;
long long dy23 = d3.y - d2.y;
if (dx12 == 0) {
if (dx12 == dx23) {
return true;
} else {
return false;
}
}
if (dy12 / (double) dx12 == dy23 / (double) dx23) {
return true;
} else {
return false;
}
}
drawvec remove_collinear(drawvec const &geom) {
drawvec out;
for (size_t i = 0; i < geom.size(); i++) {
if (i > 0 && i + 1 < geom.size() &&
geom[i].op == VT_LINETO && geom[i + 1].op == VT_LINETO &&
same_slope(out.back(), geom[i], geom[i + 1])) {
continue;
}
out.push_back(geom[i]);
}
return out;
}
drawvec scale_polygon(drawvec const &geom, int z, int detail) {
double scale = 1LL << (32 - detail - z);
drawvec out;
for (size_t i = 0; i < geom.size(); i++) {
if (geom[i].op == VT_MOVETO) {
size_t j;
for (j = i + 1; j < geom.size(); j++) {
if (geom[j].op != VT_LINETO) {
break;
}
}
drawvec ring;
// k + 1 to avoid copying duplicate last point for the moment
for (size_t k = i; k + 1 < j; k++) {
ring.emplace_back(geom[k].op, std::llround(geom[k].x / scale), std::llround(geom[k].y / scale));
}
for (size_t k = 0; k < ring.size(); k++) {
double scaled_area_orig = triangle_area(geom, i, k, ring.size()) / scale / scale;
double area_scaled = triangle_area(ring, 0, k, ring.size());
// Was this ear's winding corrupted during scaling?
// But ignore ears with area less than one pixel,
// to avoid excessive fiddling with the geometry
if ((scaled_area_orig > 1 && area_scaled < -1) ||
(scaled_area_orig < -1 && area_scaled > 1)) {
// jitter one of the coordinates to try to fix it,
// on the theory that a slightly-wrong ring is
// better than an entirely missing ring.
//
// getting to an area of 0 is good enough because
// that is addressed in fix_opposites()
for (long long dx = -1; dx <= 1; dx++) {
for (long long dy = -1; dy <= 1; dy++) {
drawvec altered = ring;
altered[0 + (k + 1) % ring.size()].x += dx;
altered[0 + (k + 1) % ring.size()].y += dy;
double area_altered = triangle_area(altered, 0, k, altered.size());
if ((scaled_area_orig > 1 && area_altered >= 0) ||
(scaled_area_orig < -1 && area_altered <= 0)) {
ring = altered;
dx = dy = INT_MAX; // break from both loops
break;
}
}
}
}
}
for (auto const &g : ring) {
out.push_back(g);
}
// close the ring
out.push_back(draw(VT_LINETO, ring[0].x, ring[0].y));
i = j - 1;
}
}
return out;
}
drawvec clean_polygon(drawvec geom, long long extent) {
// decompose polygon rings into segments
std::vector<std::pair<point, point>> segments;
for (size_t i = 0; i < geom.size(); i++) {
if (geom[i].op == VT_MOVETO) {
size_t j;
for (j = i + 1; j < geom.size(); j++) {
if (geom[j].op != VT_LINETO) {
break;
}
}
for (size_t k = i; k + 1 < j; k++) {
std::pair<point, point> seg = std::make_pair(
point(geom[k].x, geom[k].y),
point(geom[k + 1].x, geom[k + 1].y));
if (seg.first.x != seg.second.x ||
seg.first.y != seg.second.y) {
segments.push_back(seg);
}
}
i = j - 1;
}
}
// snap-round intersecting segments
snap_round(segments, extent);
// reassemble segments into rings
std::vector<ring_area> rings = reassemble(segments);
std::sort(rings.begin(), rings.end());
// determine ring nesting
for (size_t i = 0; i < rings.size(); i++) { // from largest to smallest abs area
for (ssize_t j = i - 1; j >= 0; j--) { // from smallest to largest abs area of already examined
if (encloses(rings[j], rings[i])) {
if (rings[i].area < 0 && rings[j].area > 0) {
// inner ring inside an outer ring;
// attribute it to the outer ring
rings[j].children.push_back(i);
} else if (rings[i].area < 0 && rings[j].area < 0) {
// inner ring within inner ring
rings[i].geom.clear();
} else if (rings[i].area > 0 && rings[j].area > 0) {
// outer ring within outer ring
rings[i].geom.clear();
} else {
// outer ring within an inner ring;
// this is fine, but it is treated as a new outer ring in the tile,
// not output in a hierarchy with the enclosing rings
}
break;
}
}
}
drawvec ret;
for (size_t i = 0; i < rings.size(); i++) {
if (rings[i].area < 0 && rings[i].geom.size() != 0) {
// drop top-level holes
continue;
}
for (auto const &g : rings[i].geom) {
ret.emplace_back(g.op, g.x / SCALE, g.y / SCALE);
}
for (auto child : rings[i].children) {
for (auto const &g : rings[child].geom) {
ret.emplace_back(g.op, g.x / SCALE, g.y / SCALE);
}
rings[child].geom.clear();
}
}
// remove collinear points
return remove_collinear(ret);
}