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Consistent indent style with clang-format

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This commit is contained in:
Eric Fischer
2015-06-03 11:22:13 -07:00
parent d9ff3f78fc
commit 8a1f0d83e1
14 changed files with 127 additions and 134 deletions
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clip.c
+9 -9
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@@ -29,37 +29,37 @@ int clip(double *x0, double *y0, double *x1, double *y1, double xmin, double ymi
int outcode1 = computeOutCode(*x1, *y1, xmin, ymin, xmax, ymax);
int accept = 0;
int changed = 0;
while (1) {
if (!(outcode0 | outcode1)) { // Bitwise OR is 0. Trivially accept and get out of loop
if (!(outcode0 | outcode1)) { // Bitwise OR is 0. Trivially accept and get out of loop
accept = 1;
break;
} else if (outcode0 & outcode1) { // Bitwise AND is not 0. Trivially reject and get out of loop
} else if (outcode0 & outcode1) { // Bitwise AND is not 0. Trivially reject and get out of loop
break;
} else {
// failed both tests, so calculate the line segment to clip
// from an outside point to an intersection with clip edge
double x = *x0, y = *y0;
// At least one endpoint is outside the clip rectangle; pick it.
int outcodeOut = outcode0 ? outcode0 : outcode1;
// Now find the intersection point;
// use formulas y = y0 + slope * (x - x0), x = x0 + (1 / slope) * (y - y0)
if (outcodeOut & TOP) { // point is above the clip rectangle
if (outcodeOut & TOP) { // point is above the clip rectangle
x = *x0 + (*x1 - *x0) * (ymax - *y0) / (*y1 - *y0);
y = ymax;
} else if (outcodeOut & BOTTOM) { // point is below the clip rectangle
} else if (outcodeOut & BOTTOM) { // point is below the clip rectangle
x = *x0 + (*x1 - *x0) * (ymin - *y0) / (*y1 - *y0);
y = ymin;
} else if (outcodeOut & RIGHT) { // point is to the right of clip rectangle
y = *y0 + (*y1 - *y0) * (xmax - *x0) / (*x1 - *x0);
x = xmax;
} else if (outcodeOut & LEFT) { // point is to the left of clip rectangle
} else if (outcodeOut & LEFT) { // point is to the left of clip rectangle
y = *y0 + (*y1 - *y0) * (xmin - *x0) / (*x1 - *x0);
x = xmin;
}
// Now we move outside point to intersection point to clip
// and get ready for next pass.
if (outcodeOut == outcode0) {