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Fix backwards conditional

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Erica Fischer
2024-09-13 11:32:51 -07:00
parent 56655e6ebf
commit 7a0878da9b
2 changed files with 8 additions and 7 deletions
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clip.cpp
+5 -4
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@@ -1157,14 +1157,14 @@ static void feature_out(std::vector<tile_feature> const &features, mvt_layer &ou
std::map<std::string, size_t> numeric_out_field;
for (size_t i = 0; i + 1 < features[0].tags.size(); i += 2) {
auto f = attribute_accum.find(features[0].layer->keys[features[0].tags[i]]);
const std::string &key = features[0].layer->keys[features[0].tags[i]];
auto f = attribute_accum.find(key);
if (f != attribute_accum.end()) {
// this attribute has an accumulator, so convert it
full_keys.push_back(features[0].layer->keys[features[0].tags[i]]);
full_values.push_back(mvt_value_to_serial_val(features[0].layer->values[features[0].tags[i + 1]]));
} else if (accumulate_numeric && features[0].layer->values[features[0].tags[i + 1]].is_numeric()) {
// convert numeric for accumulation
const std::string &key = features[0].layer->keys[features[0].tags[i]];
numeric_out_field.emplace(key, full_keys.size());
full_keys.push_back(key);
full_values.push_back(mvt_value_to_serial_val(features[0].layer->values[features[0].tags[i + 1]]));
@@ -1202,8 +1202,9 @@ static void feature_out(std::vector<tile_feature> const &features, mvt_layer &ou
// same attribute, we want to use that one instead of this one.
for (auto const &op : numeric_operations) {
auto compound_found = keys.find("tipppecanoe:" + op.first + ":" + key);
if (compound_found == keys.end()) {
std::string compound_key = "tipppecanoe:" + op.first + ":" + key;
auto compound_found = keys.find(compound_key);
if (compound_found != keys.end()) {
// found, so skip this one
} else {
// not found, so accumulate this one