Fix my assumption that wagyu can work on multiple outer rings at once

This commit is contained in:
Erica Fischer
2023-10-27 15:02:27 -07:00
parent 0c4b5d089b
commit 5afc80d778
+49 -46
View File
@@ -5,9 +5,41 @@ using Coord = long long;
using N = size_t;
using Point = std::array<Coord, 2>;
drawvec reinforce(drawvec const &pts, std::vector<std::vector<Point>> polygon, double scale) {
std::vector<N> indices = mapbox::earcut<N>(polygon);
drawvec out2;
for (size_t i = 0; i + 2 < indices.size(); i += 3) {
std::vector<double> lengths;
for (size_t j = 0; j < 3; j++) {
size_t v1 = i + j;
size_t v2 = i + ((j + 1) % 3);
size_t v3 = i + ((j + 2) % 3);
double px, py;
if (distance_from_line(pts[indices[v1]].x, pts[indices[v1]].y, // the point
pts[indices[v2]].x, pts[indices[v2]].y, // start of opposite side
pts[indices[v3]].x, pts[indices[v3]].y, // end of opposite side
&px, &py) < scale) {
double ang = atan2(pts[indices[v1]].y - py, pts[indices[v1]].x - px);
// make a new triangle that is not so flat
out2.push_back(draw(VT_MOVETO, pts[indices[v2]].x, pts[indices[v2]].y));
out2.push_back(draw(VT_LINETO, pts[indices[v3]].x, pts[indices[v3]].y));
out2.push_back(draw(VT_LINETO, px + scale * cos(ang), py + scale * sin(ang)));
out2.push_back(draw(VT_LINETO, pts[indices[v2]].x, pts[indices[v2]].y));
}
}
}
return out2;
}
drawvec fix_by_triangulation(drawvec const &dv, int z, int detail) {
std::vector<std::vector<Point>> polygon;
drawvec out;
drawvec out, out2;
double scale = 1LL << (32 - z - detail);
for (size_t i = 0; i < dv.size(); i++) {
@@ -19,6 +51,17 @@ drawvec fix_by_triangulation(drawvec const &dv, int z, int detail) {
}
}
if (get_area(dv, i, j) > 0) {
// outer ring, so process whatever we have so far
drawvec additional = reinforce(out, polygon, scale);
for (auto const &d : additional) {
out2.push_back(d);
}
polygon.clear();
out.clear();
}
std::vector<Point> ring;
// j - 1 because earcut docs indicate that it doesn't expect
// a duplicate last point in each ring
@@ -33,52 +76,12 @@ drawvec fix_by_triangulation(drawvec const &dv, int z, int detail) {
}
}
std::vector<N> indices = mapbox::earcut<N>(polygon);
drawvec out2;
for (size_t i = 0; i + 2 < indices.size(); i += 3) {
std::vector<double> lengths;
for (size_t j = 0; j < 3; j++) {
size_t v1 = i + j;
size_t v2 = i + ((j + 1) % 3);
size_t v3 = i + ((j + 2) % 3);
double px, py;
if (distance_from_line(out[indices[v1]].x, out[indices[v1]].y, // the point
out[indices[v2]].x, out[indices[v2]].y, // start of opposite side
out[indices[v3]].x, out[indices[v3]].y, // end of opposite side
&px, &py) < 2 * scale) {
double ang = atan2(out[indices[v1]].y - py, out[indices[v1]].x - px);
// make a new triangle that is not so flat
out2.push_back(draw(VT_MOVETO, out[indices[v2]].x, out[indices[v2]].y));
out2.push_back(draw(VT_LINETO, out[indices[v3]].x, out[indices[v3]].y));
out2.push_back(draw(VT_LINETO, px + 2 * scale * cos(ang), py + 2 * scale * sin(ang)));
out2.push_back(draw(VT_LINETO, out[indices[v2]].x, out[indices[v2]].y));
}
}
drawvec additional = reinforce(out, polygon, scale);
for (auto const &d : additional) {
out2.push_back(d);
}
// re-close the rings from which we removed the last points earlier
for (size_t i = 0; i < out.size(); i++) {
if (out[i].op == VT_MOVETO) {
size_t j;
for (j = i + 1; j < out.size(); j++) {
if (out[j].op != VT_LINETO) {
break;
}
}
for (size_t k = i; k < j; k++) {
out2.push_back(out[k]);
}
out2.push_back(draw(VT_LINETO, out[i].x, out[i].y));
i = j - 1;
}
for (auto const &d : dv) {
out2.push_back(d);
}
return out2;